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    ® IGCSE is a registered trademark. This document consists of 8  printed pages. © UCLES 2018 [Turn over    Cambridge Assessment International Education Cambridge International Advanced Subsidiary and Advanced Level  PHYSICS 9702/22 Paper 2 AS Level Structured Questions March 2018  MARK SCHEME Maximum Mark: 60 Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Examiners were instructed to award marks. It does not indicate the details of the discussions that took place at an Examiners’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge International will not enter into discussions about these mark schemes. Cambridge International is publishing the mark schemes for the March 2018 series for most Cambridge IGCSE ® , Cambridge International A and AS Level components and some Cambridge O Level components.  9702/22 Cambridge International AS/A Level – Mark Scheme PUBLISHED  March 2018 © UCLES 2018 Page 2 of 8 Generic Marking Principles These general marking principles must be applied by all examiners when marking candidate answers. They should be applied alongside the specific content of the mark scheme or generic level descriptors for a question. Each question paper and mark scheme will also comply with these marking principles. GENERIC MARKING PRINCIPLE 1: Marks must be awarded in line with: ã  the specific content of the mark scheme or the generic level descriptors for the question ã  the specific skills defined in the mark scheme or in the generic level descriptors for the question ã  the standard of response required by a candidate as exemplified by the standardisation scripts. GENERIC MARKING PRINCIPLE 2: Marks awarded are always whole marks  (not half marks, or other fractions). GENERIC MARKING PRINCIPLE 3: Marks must be awarded positively : ã  marks are awarded for correct/valid answers, as defined in the mark scheme. However, credit is given for valid answers which go beyond the scope of the syllabus and mark scheme, referring to your Team Leader as appropriate ã  marks are awarded when candidates clearly demonstrate what they know and can do ã  marks are not deducted for errors ã  marks are not deducted for omissions ã  answers should only be judged on the quality of spelling, punctuation and grammar when these features are specifically assessed by the question as indicated by the mark scheme. The meaning, however, should be unambiguous. GENERIC MARKING PRINCIPLE 4: Rules must be applied consistently e.g. in situations where candidates have not followed instructions or in the application of generic level descriptors.  9702/22 Cambridge International AS/A Level – Mark Scheme PUBLISHED  March 2018 © UCLES 2018 Page 3 of 8 GENERIC MARKING PRINCIPLE 5: Marks should be awarded using the full range of marks defined in the mark scheme for the question (however; the use of the full mark range may be limited according to the quality of the candidate responses seen). GENERIC MARKING PRINCIPLE 6: Marks awarded are based solely on the requirements as defined in the mark scheme. Marks should not be awarded with grade thresholds or grade descriptors in mind.  9702/22 Cambridge International AS/A Level – Mark Scheme PUBLISHED  March 2018 © UCLES 2018 Page 4 of 8 Question Answer Marks 1(a) acceleration: vector speed: scalar power: scalar  All three correct scores 2 marks. Only two correct scores 1 mark. B2 1(b)(i) time = 0.43   /   1.1 = 0.39   s A1 1(b)(ii) s  = ut   + ½ at 2  = ½ ×  9.81 ×  0.39 2   C1 = 0.75   m   A1 1(b)(iii) 1 horizontal line at a non-zero value of a . B1 2 curved line from srcin with increasing gradient. B1 1(c) acceleration (of free fall) is unchanged   /   not dependent on mass and so no effect (on time taken). A1 Question Answer Mark 2(a)(i) force ×  distance moved in the direction of the force B1 2(a)(ii) energy (of a mass/body) due to motion   /   speed   /   velocity B1 2(b)(i) 1 E   = ½ mv    2   C1 ( ∆ ) E   = ½ ×  580 ×  (22 2  – 12 2 ) = 9.9 ×  10 4   J   A1 2 ( ∆ ) E   = mg  ( ∆ ) h   ∆ E   = 580 ×  9.81 ×  13 C1 = 7.4 ×  10 4 J A1
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