# Area of Triangles

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Area of Triangles. A. b. B. C. a. The area of a triangle can be found from two sides and the angle between them. Area of triangle = 1 / 2 absinC. Also. Area of triangle = 1 / 2 acsinB. Area of triangle = 1 / 2 bcsinA. Ex1. A. 2.5cm. 70 °. B. C. 4cm. M. 35m. 130 °. K.
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Area of TrianglesAbBCaThe area of a triangle can be found from two sides and the angle between them.Area of triangle = 1/2absinCAlsoArea of triangle = 1/2acsinBArea of triangle = 1/2bcsinAEx1A2.5cm70°BC4cmM35m130°KL30mArea of triangle = 1/2absinC= 0.5 X 4 X 2.5 x sin70°= 4.7cm2Ex2Area of triangle = 1/2kmsinL= 0.5 X 30 X 35 x sin130°= 402m2Ex3Find the area of this parallelogram.PArea  = 1/2pqsinR22cm= 0.5 X 11 X 22 X sin66° = 110.5cm266°RQ11cmSo area of parallelogram = 2 X 110.5 = 221cm2Ex4 Find the area of this quadrilateral.15cm14cm15cm76.6°76.6°14cmArea = 0.5 X 14 X 15 x sin76.6°= 102cm220cm21cm52°20cm21cm52°Area = 0.5 X 20 X 21 x sin52°Total area = 267cm2= 165cm2Obtuse Angles A B A+B sinA° sinB° 20 1601800.3420.342 35 1451800.5740.574 70 1101800.9400.940 43 1371800.6820.682CONCLUSIONIf A + B = 180 then sinA° = sinB°Ex4sinx° = 0.643so x = sin-10.643= 40° or 140°
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